110 lines
1.7 KiB
C++
110 lines
1.7 KiB
C++
#include "easy2d.h"
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#include <assert.h>
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Scene::Scene()
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{
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}
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Scene::~Scene()
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{
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clearAllChildren();
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}
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void Scene::_exec()
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{
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// active 标志画面是否取得焦点
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bool active = true;
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// 逆序执行，最后绘制的节点（即位于画面最上方）最先被访问
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for (int i = int(m_vChildren.size()) - 1; i >= 0; i--)
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{
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assert(m_vChildren[i]);
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if (m_vChildren[i]->_exec(active)) // 执行节点程序
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{
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active = false; // 若子节点取得焦点，将标志置 false
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}
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}
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}
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void Scene::_onDraw()
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{
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// 绘制所有节点
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for (auto child : m_vChildren)
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{
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assert(child);
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child->_onDraw();
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}
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}
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void Scene::onEnter()
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{
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}
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void Scene::onExit()
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{
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}
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void Scene::add(Node * child, int zOrder)
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{
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// 断言添加的节点非空
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assert(child);
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// 设置节点的父场景
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child->setParentScene(this);
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// 设置 z 轴顺序
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child->setZOrder(zOrder);
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// 对象的引用计数加一
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child->retain();
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// 按 z 轴顺序插入节点
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size_t size = m_vChildren.size();
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for (unsigned i = 0; i <= size; i++)
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{
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if (i == size)
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{
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m_vChildren.push_back(child);
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break;
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}
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else
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{
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auto temp = m_vChildren.at(i);
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if (temp->getZOrder() > zOrder)
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{
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m_vChildren.insert(m_vChildren.begin() + i, child);
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break;
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}
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}
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}
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}
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bool Scene::del(Node * child)
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{
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// 断言节点非空
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assert(child);
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// 寻找是否有相同节点
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std::vector<Node*>::iterator iter;
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for (iter = m_vChildren.begin(); iter != m_vChildren.end(); iter++)
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{
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// 找到相同节点
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if (*iter == child)
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{
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// 对象的引用计数减一
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(*iter)->release();
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// 去掉该节点
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m_vChildren.erase(iter);
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return true;
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}
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}
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// 未找到该节点返回 false
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return false;
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}
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void Scene::clearAllChildren()
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{
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// 所有节点的引用计数减一
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for (auto child : m_vChildren)
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{
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child->release();
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}
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// 清空储存节点的容器
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m_vChildren.clear();
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} |